Question 1. Draw out the possible outcomes as a 6 by 6 square grid. Circle the outcomes that add up to 5, e.g. (4,1) (3,2) etc. They should lie on a 45 degree line. So what's the probability of throwing 2? There's only one way of getting that, (1,1). So the probability of getting a 2 is $1/36$. How about 3? There are two ways of doing that: (2,1) or (1,2). So that gives $P(3) = 2/36$. How about 4? There's (1,3), (2,2), and (3,1). So the probability of this $P(4) = 3/36$.